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2a^2-5a-250=0
a = 2; b = -5; c = -250;
Δ = b2-4ac
Δ = -52-4·2·(-250)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-45}{2*2}=\frac{-40}{4} =-10 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+45}{2*2}=\frac{50}{4} =12+1/2 $
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